MCQ
A parachutist after bailing out falls $20\,\,m$ without friction. When parachute opens, it decelerates at $2\,\,m/s^2.$  He reached the ground with a speed with a speed of $4\,\,m/s.$  At what height, did he bail out ?......$m$
  • A
    $91$
  • B
    $182$
  • C
    $293$
  • $116$

Answer

Correct option: D.
$116$
d
$\mathrm{h}=\frac{\mathrm{u}^{2}-\mathrm{v}^{2}}{2 \mathrm{a}}$

$\mathrm{h}=\frac{400-16}{4}=\frac{384}{4}$

$h=96 \mathrm{m}$

$\mathrm{H}=20+96=116 \mathrm{m}$

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