A parallel plate capacitor with air between plates has a capacitance of $8\,\mu F$ what will be capacitance if distance between plates is reduced by half, and the space between them is filled with a substance of dielectric constant $6$ ?.....$\mu F$
Medium
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${{\rm{C}}^\prime } = \frac{{{\varepsilon _{\rm{r}}}{\varepsilon _0}{\rm{A}}}}{{\rm{d}}}{\rm{ }}{{\rm{C}}^\prime } \propto {\varepsilon _{\rm{r}}}$
${{\rm{C}}^\prime } \propto \frac{1}{d}$
$ \mathrm{C}^{\prime} \Rightarrow 8 \times 6 \times 2 $
${{\rm{C}}^\prime } = 96\,\mu {\rm{f}}$
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