MCQ
A particle executes harmonic motion with an angular velocity and maximum acceleration of $3.5\, rad/sec$ and $ 7.5\, m/s^2$ respectively. The amplitude of oscillation is .... $m$
- A$0.28$
- B$0.36$
- C$0.53$
- ✓$0.61$
✓
Answer
Correct option: D.
$0.61$
d
(d) ${A_{\max }} = a{\omega ^2} $
(d) ${A_{\max }} = a{\omega ^2} $
$\Rightarrow a = \frac{{{A_{\max }}}}{{{\omega ^2}}} = \frac{{7.5}}{{{{(3.5)}^2}}} = 0.61\;m$
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