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Simple Harmonic Motion — JEE physics STD 12 Science — Question

CBSE BoardEnglish MediumSTD 12 ScienceJEE physicsSimple Harmonic Motion1 Mark
MCQ
A particle executes harmonic motion with an angular velocity and maximum acceleration of $3.5 rad / sec$ and $7.5 m / s$ respectively. The amplitude of oscillation is
  • A
    $0.28 m$
  • B
    $0.36 m$
  • C
    $0.53 m$
  • ✓
    $0.61 m$
✓

Answer

Correct option: D.
$0.61 m$
(d) $A_{\max }=a \omega^2 \Rightarrow a=\frac{A_{\max }}{\omega^2}=\frac{7.5}{(3.5)^2}=0.61 \mathrm{~m}$

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