A particle executes simple harmonic oscillation with an amplitude $a.$ The period of oscillation is $T.$ The minimum time taken by the particle to travel half of the amplitude from the equilibrium position is
A$\frac{T}{8}$
B$\;\frac{T}{{12}}$
C$\;\frac{T}{2}$
D$\;\frac{T}{4}$
AIPMT 2007, Medium
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B$\;\frac{T}{{12}}$
b $x(t)=a \sin \omega t$ $(from \,the\, equilibrium\, position)$
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