MCQ
A particle executing linear SHM has velocities $v _1$ and $v _2$ at distances $x _1$ and $x _2$, respectively, from the mean position. The angular velocity of the particle is
  • A
    $\sqrt{\frac{x_1^2-x_2^2}{v_2^2-v_1^2}}$
  • $\sqrt{\frac{v_2^2-v_1^2}{x_1^2-x_2^2}}$
  • C
    $\sqrt{\frac{x_1^2+x_2^2}{v_2^2+v_1^2}}$
  • D
    $\sqrt{\frac{v_2^2+v_1^2}{x_1^2+x_2^2}}$.

Answer

Correct option: B.
$\sqrt{\frac{v_2^2-v_1^2}{x_1^2-x_2^2}}$
$\sqrt{\frac{v_2^2-v_1^2}{x_1^2-x_2^2}}$

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