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STD 11 - 2. motion in straight line — NEET STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceNEETSTD 11 - 2. motion in straight line4 Marks
MCQ
A particle experiences a constant acceleration for $20\, seconds$ after starting from rest. If it travels a distance $s_1$ in the first $10\, seconds$ and distance $s_2$ in the next $10\, seconds$, then :-
  • A
    $s_2 = s_1$
  • B
    $s_2 = 2s_1$
  • ✓
    $s_2 = 3s_1$
  • D
    $s_2 = 4s_1$
✓

Answer

Correct option: C.
$s_2 = 3s_1$
c
As acceleration is constant for 20 sec after starting from rest so

$\mathrm{S} 1=\mathrm{ut}+1 / 2 \times \mathrm{at}^{\wedge} 2$

$\mathrm{S} 1=0 \times 10+1 / 2 \times \mathrm{a} \times 100$

$\mathrm{So}, \mathrm{S} 1=50 \mathrm{a}$

Now, $\mathrm{S} 1+\mathrm{S} 2=0 \times 20+1 / 2 \times \mathrm{a} \times 20^{\wedge} 2$

$\mathrm{S} 1+\mathrm{S} 2=200 \mathrm{a}$

As, $\mathrm{S} 1=50 \mathrm{a}$

$50 a+52=200 a$

$\mathrm{S} 2=150 \mathrm{a}$

Hence $\mathrm{S} 1 / \mathrm{S} 2=50 \mathrm{a} / 150 \mathrm{a}$

$\mathrm{S} 2=3 \mathrm{S} 1$

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