A particle is executing $S.H.M.$ If its amplitude is $2 \,m$ and periodic time $2$ seconds, then the maximum velocity of the particle will be
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(c) ${v_{\max }} = \omega a = \frac{{2\pi }}{T} \times a$
==> ${v_{\max }} = \frac{{2 \times \pi \times 2}}{2} = 2\pi \,\,m/s$
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