MCQ
A particle is moving in a horizontal circle with constant speed. It has constant
  • A
    Velocity
  • B
    Acceleration
  • Kinetic energy
  • D
    Displacement

Answer

Correct option: C.
Kinetic energy
c
(c) $K.E. = \frac{1}{2}m{v^2}$. Which is scalar, so it remains constant.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

A particle has initial velocity $10\,\, m/s$. It moves due to constant retarding force along the line of velocity which produces a retardation of $5\,\, m/s^2$. Then
A glass slab is subjected to a pressure of $10\, atm$. The fractional change in its volume is (Bulk modulus of glass $= 37 \times 10^9\, N\, m^{-2}$, $1\, atm = 1 \times 10^5\, N\, m^{-2}$)
Which of the following colours suffers maximum deviation in a prism
A particle of mass $m$ and charge $q$ is thrown from origin at $t = 0$ with velocity $2\hat{i}$ + $3\hat{j}$ + $4\hat{k}$ units in a region with uniform magnetic field $\vec B$ = $2\hat{i}$ units. After time $t =\frac{{\pi m}}{{qB}}$ , an electric field  is switched on such that particle moves on a straight line with constant speed. $\vec E$ may be
In the circuit shown in figure, the power which is dissipated as heat in the $6\,\Omega $ resistor is $6\,W$. What is the value of resistance $R$ in the circuit? ................ $\Omega$
In a meter bridge, the null point is found at a distance of $25\, cm$ from $A$. If now a resistance of $10\,\Omega $ is connected in parallel with $S$, the null point occurs at mid point of $AB$. The value of $R$ is ................. $\Omega$
Two semicircular rings of linear mass densities $\lambda $ and $3\lambda $ and of radius $R$ each are joining to form a complete ring. The distance of the centre of the mass of complete ring from its geometrical centre is
A $400\, pF$ capacitor is charged with a $100\, V$ battery. After disconnecting battery this capacitor is connected with another $400\, pF$ capacitor. Then find out energy loss.
Magnetic effect of current was discovered by
A single circular loop of radius $1.00\, m$ carries a current of $10.0\, mA$. It is placed in $a$ uniform magnetic field of magnitude $0.500\, T$ that is directed parallel to the plane of the loop as suggested in the figure. The magnitude of the torque exerted on the loop by the magnetic field is.