MCQ
A particle is projected from the ground with an initial speed $\upsilon $ at an angle $\theta $ with horizontal. The average velocity of the particle between its point of projection and highest point of trajectory is
- A$\frac{\upsilon }{2}\sqrt {1 + 2\,\,{{\cos }^{2\,}}\theta } $
- B$\frac{\upsilon }{2}\sqrt {1 + {{\cos }^{2\,}}\theta } $
- ✓$\frac{\upsilon }{2}\sqrt {1 + 3\,\,{{\cos }^{2\,}}\theta } $
- D$\upsilon \,\cos \,\theta $
