MCQ
A particle moves with constant angular velocity in circular path of certain radius and is acted upon by a certain centripetal force $F$. if the centripetal force $F$ is kept constant but the angular velocity is doubled, the new radius of the path (original radius $R$ ) will be
  • A
    $2R$
  • B
    $R/2$
  • $R/4$
  • D
    $4R$

Answer

Correct option: C.
$R/4$
c
(c) $F = m{\omega ^2}R$ $\therefore$ $R \propto \frac{1}{{{\omega ^2}}}$ ($m$ and $F$ are constant)

If $\omega$ is doubled then radius will become $1/4$ times i.e. $R/4$

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