MCQ
A particle moving along the $x$-axis executes simple harmonic motion, then the force acting on it is given by
  • $-A K x$
  • B
    $A \cos (K x)$
  • C
    $A \exp (-K x)$
  • D
    $A K x$

Answer

Correct option: A.
$-A K x$
For S.H.M. $F=-k x$.
$\therefore \text { Force }=\text { Mass } \times \text { Acceleration } \propto-x$
$\Rightarrow F=-A k x$, where $A$ and $k$ are positive constants.

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