MCQ
A particle moving with velocity $\vec{v}$ is acted by three forces shown by the vector triangle $\text{PQR.}$ The velocity of the particle will:
  • remain constant
  • B
    change according to the smallest force $\overrightarrow{ QR }$
  • C
    increase
  • D
    decrease

Answer

Correct option: A.
remain constant
Hint:
Image
As the three forces acting on a particle represents a triangle $($i.e., a closed loop$)$
$\therefore F_{net} = 0$
$\therefore m \vec{a}=0$
$\therefore m \frac{ d \overrightarrow{ v }}{ dt }$
$\therefore v$ remains constant
remain constant

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