MCQ
A particle starting from rest and moving with a uniform acceleration along a straight line covers distances $a$ and $b$ in successive intervals of $p$ and $q$ second. The acceleration of the particle is
  • A
    $\frac{a+b}{2(p+q)}$
  • $\frac{2 b}{(q+2 p) q}$
  • C
    $\frac{2 a}{p(p+2 p)}$
  • D
    $\frac{a+b}{(p+q)^2}$

Answer

Correct option: B.
$\frac{2 b}{(q+2 p) q}$
b
(b)

Let $x$ be the acceleration. Then

$a=\frac{1}{2}\,x p^2$

$a+b=+\frac{1}{2} x(p+q)^2$

Solving these two equations, we get

$x=\frac{2 b}{(q+2 p) q}$

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