MCQ
$A$ particle starts from the point $(0m, 8m)$ and moves with uniform velocity of $3\, \hat i \,m/s$. After $5$ seconds, the angular velocity of the particle about the origin will be :
  • A
    $\frac{8}{{289}} \,rad/s$
  • B
    $\frac{3}{{8}} \,rad/s$
  • $\frac{24}{{289}} \,rad/s$
  • D
    $\frac{8}{{17}} \,rad/s$

Answer

Correct option: C.
$\frac{24}{{289}} \,rad/s$
c
at $t=5$ sec, $x=3 \times 5=15 \mathrm{m}$

$y=8$

$\omega=\frac{v \sin \theta}{r} \Rightarrow \omega=\frac{3}{\sqrt{289}} \times \frac{8}{\sqrt{289}}$

$\omega=\frac{24}{289} r a d / \mathrm{sec}$

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