$T=2 \pi \sqrt{\frac{l}{g}}$ or $T \propto \sqrt{\frac{l}{g}}$
when the elevator is accelerating downwards, the net gravitational acceleration is $(g-a),$ so, the time period when elevation is accelerating downwards, is greatest.

$(A)$ $E_1 \omega_1=E_2 \omega_2$ $(B)$ $\frac{\omega_2}{\omega_1}=n^2$ $(C)$ $\omega_1 \omega_2= n ^2$ $(D)$ $\frac{E_1}{\omega_1}=\frac{E_2}{\omega_2}$