A perfectly elastic uniform string is suspended vertically with its upper end fixed to the ceiling and the lower end loaded with the weight. If a transverse wave is imparted to the lower end of the string, the pulse will
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$\boldsymbol{v}=\sqrt{\frac{T}{\mu}}=\sqrt{\frac{w+\mu x g}{\mu}}=\sqrt{\frac{w}{\mu}+x g}$

$\Rightarrow v^{2}=\frac{w}{\mu}+x g \Rightarrow 2 v \frac{d v}{d x}=g \Rightarrow a=\frac{g}{2}$

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