MCQ
A photocell employs photoelectric effect to convert
  • A
    change in the frequency of light into a change in the electric current
  • B
    change in the frequency of light into a change in electric voltage
  • change in the intensity of illumination into a change in photoelectric current
  • D
    change in the intensity of illumination into a change in the work function of the photocathode.

Answer

Correct option: C.
change in the intensity of illumination into a change in photoelectric current
c
The photoelectric current is directly proportional to the intensity of illumination. Therefore a change in the intensity of the incident radiation will change the photocurrent also.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

If narrow slit of width $2\, mm$ is illuminated by monochromatic light of wavelength $500\, nm$, then the distance between the first minima of both side on a screen at a distance of $1\, m$ is.......$mm$
In the given circuit the value of $\left|\frac{I_1+I_3}{I_2}\right|$ is
In a current carrying conductor the net charge is:
A hollow lens is made of thin glass and in the shape of a double concave lens. It can be filled with air, water of refractive index $1.33$ or $CS _2$ of refractive index $1.6$. It will act as a diverging lens, if it is
Compton effect supports that
In the following circuit, $1 \,\Omega$ resistor dissipates power $P$. If the resistor is replaced by $9 \,\Omega$, the power dissipated in it is
A compass needle is free to rotate in a horizontal plane. It’s magnetic moment is $60\ Am^2$ . When it is pointing geographical north, it experiences a torque of $1.2 × 10^{-3}\ Nm$ due to earth’s magnetic field. If earth’s magnetic field in horizontal direction is $40 × 10^{-6}\ T$ , what is declination.....$^o$ at that place ?
Half angular width of the central maxima in the fraunhaufer diffraction due to slit width $\frac{{1200}}{{\sqrt 2 }}\ \mu m $ is $45^o$. Then wavelength of the light is......$\mu m $
A plane electromagnetic wave of wavelength $\lambda $ has an intensity $I.$  It is propagating along the positive $Y-$  direction. The allowed expressions for the electric and magnetic fields are given by
If ${l_1},\,{l_2},\,{l_3}$ are the lengths of the emitter, base and collector of a transistor then