MCQ
A physical quantity is given as $y =\frac{a b^3}{c^2}$. If $\Delta a , \Delta b , \Delta c$ are absolute errors, the possible fractional error in $y$ is .....
- A$\frac{\Delta y}{y}=\frac{\Delta a \Delta b}{2 \Delta c }$
- ✓$\frac{\Delta y}{y}=\frac{\Delta a}{a}+3 \frac{\Delta b}{b}+2 \frac{\Delta c}{c}$
- C$\frac{\Delta y}{y}=\frac{\Delta a}{a}+\left(\frac{\Delta b}{a}\right)^3+\left(\frac{\Delta c}{c}\right)^2$
- D$\frac{\Delta y}{y}=\frac{\Delta a}{a}+\frac{\Delta b}{a}+\frac{\Delta c}{c}$