Question
A physical quantity Q is given by$\text{Q}= \frac{\text{A}^2\text{B}^\frac{3}{2}}{\text{C}^{+4}\text{D}^\frac{1}{2}}$
The percentage error in A, B, C, D are 1%, 2%, 4%, 2% respectively. Find the percentage error in Q.

Answer

$\% \text{ error in} \text{ Q}=2 \Big(\frac{\text{dA}}{A}\times100\Big)+\frac{3}{2}\Big(\frac{\text{dB}}{\text{B}}\times100\Big)$ $+4\Big(\frac{\text{dC}}{\text{C}}\times100\Big)+\frac{1}{2}\Big(\frac{\text{dB}}{\text{D}}\times100\Big) $ $= 2\times1+\frac{3}{2}\times2+4\times4+\frac{1}{2}\times2$ $=2+3+16+1= 22\%$

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