$=2 \times 10^{11} \times \frac{1}{100} \times \mathrm{A}$
$\mathrm{n}=\frac{1}{2 \times 1.5} \sqrt{\frac{\mathrm{F}}{\mathrm{Ad}}}=\frac{1}{3} \sqrt{\frac{2 \times 10^{9} \mathrm{A}}{\mathrm{A} \times 7.7 \times 10^{8}}}$
$\mathrm{n}=170 \mathrm{Hz}$
${x_1} = a\sin (\omega \,t + {\phi _1})$, ${x_2} = a\sin \,(\omega \,t + {\phi _2})$
If in the resultant wave the frequency and amplitude remain equal to those of superimposing waves. Then phase difference between them is