b
Given equation of wave
$\vec{E}=\vec{E}_{0}(4 \times \overrightarrow{10} x-50 t)$
Comparing with general equation of wave,
$\vec{E}=\vec{E}_{0}(k x-w t)$
we get,
$w=50$ rad $/ s . k=4 \times 10^{-7} m^{-1}$
Thus velocity of wave,
$v=\frac{w}{k}=\frac{50}{4 \times 10^{-7}}=1.25 \times 10^{8} \mathrm{m} / \mathrm{s}$
so, refractive index of medium,
$\mu=\frac{e}{v}=\frac{3 \times 10^{8}}{1.25 \times 10^{8}}=2.4$
using, $u^{2}=k m . k e[\mathrm{km}$ and ke are magnetic and dielectric di - constants]
as medium is non diamagnetic, $k m=1$
$\Rightarrow k e=\mu^{2}=(2.4)^{2} \Rightarrow k e=5.76$