MCQ
A pole $6m$ high casts a shadow $2\sqrt3\text{m}$ long on the ground, then the sun’s elevation is :
- ✓$60^\circ$
- B$30^\circ$
- C$45^\circ$
- D$75^\circ$
✓
Answer
Correct option: A.
$60^\circ$
Let height $= 6m$ lenght of shadow $=2\sqrt{3\text{m}}$
$\theta$ is angle of elevation $\tan\theta=\frac{\text{(height)}}{\text{(Shadow length)}}$
$=\frac{6}{2}\sqrt3=\sqrt3$
$\theta=\frac{\pi}{3}$
Angle of inclination is $= 60^\circ .$
$\theta$ is angle of elevation $\tan\theta=\frac{\text{(height)}}{\text{(Shadow length)}}$
$=\frac{6}{2}\sqrt3=\sqrt3$
$\theta=\frac{\pi}{3}$
Angle of inclination is $= 60^\circ .$
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