MCQ
A pole $6m$ high casts a shadow $2\sqrt{3}\text{m}$ long on the ground, then the Sun's elevation is :
- ✓$60^\circ$
- B$45^\circ$
- C$30^\circ$
- D$90^\circ$
✓
Answer
Correct option: A.
$60^\circ$
The sun's elevation angle will be opposite to the side which depicts the height of the pole, and base will be the length of the shadow.
$\text{Base}=2\sqrt{3}\text{m}$
$\text{height = 6m}$
$\tan(\theta)=\frac{6}{2\sqrt{3}}=\sqrt{3}$
$\theta=\tan^{-1}(\sqrt{3})$
$=60^\circ$
$\theta$ being the angle of elevation.
$\text{Base}=2\sqrt{3}\text{m}$
$\text{height = 6m}$
$\tan(\theta)=\frac{6}{2\sqrt{3}}=\sqrt{3}$
$\theta=\tan^{-1}(\sqrt{3})$
$=60^\circ$
$\theta$ being the angle of elevation.
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