MCQ
A pole stands vertically, inside a triangular park $\text{ABC}$. If the angle of elevation of the top of the pole from each corner of the park is same, then the foot of the pole is at the :
- Acentriod
- ✓circumcentre
- Cincentre
- Dorthocentre
✓
Answer
Correct option: B.
circumcentre
If angle of elevation $(p)$ is same from all the vertices then the Pole must be at Equal Distance from each of the vertices which will be $= R\ ($Circumradius$)$
as $\tan\text{p}=\frac{\text{H}}{\text{R}}$
$\Rightarrow\frac{\text{H}}{\tan\text{p}}\ [$which is same from all vertices$]$
therefore, the pole must be lying on the Circumcenter
as $\tan\text{p}=\frac{\text{H}}{\text{R}}$
$\Rightarrow\frac{\text{H}}{\tan\text{p}}\ [$which is same from all vertices$]$
therefore, the pole must be lying on the Circumcenter
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