MCQ
A potential divider circuit is shown in figure. The output voltage $V_0$ is


- A$4 \mathrm{~V}$
- B$2 \ \mathrm{mV}$
- ✓$0.5 \mathrm{~V}$
- D$12\ \mathrm{mV}$

$ i=\frac{4}{4000}=\frac{1}{1000} \mathrm{~A} $
$ V_0=i \cdot R=\frac{1}{1000} \times 500=0.5 \mathrm{~V}$
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