MCQ
A power transmission line feeds input power at $2300\,V$ to a step down transfonner with its primary windings having  $4000$ turns, giving the output power at $230\,V.$  If the current in the primary of the transformer is  $5\,A,$ and its efficiency is $90\%,$  the output current would be......$A$
  • A
    $20$
  • B
    $40$
  • $45$
  • D
    $25$

Answer

Correct option: C.
$45$
c
Given $: V_{P}=2300\, \mathrm{V}, V_{s}=230\, \mathrm{V}, I_{P}=5\, \mathrm{A}$

$\eta=90 \%=0.9$

Efficiency $\eta=0.9=\frac{P_{s}}{P_{p}} \Rightarrow P_{s}=0.9 P_{p}$

$\mathrm{V}_{\mathrm{s}} \mathrm{I}_{\mathrm{s}}=0.9 \times \mathrm{V}_{\mathrm{P}} \mathrm{I}_{\mathrm{P}} \quad(\because \mathrm{P}=\mathrm{VI})$

${I_s} = \frac{{0.9 \times 2300 \times 5}}{{230}} = 45{\mkern 1mu} {\text{A}}$

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