MCQ
A precipitate of calcium oxalate will not dissolve in
- A$HCl$
- B$HN{O_3}$
- CAquaregia
- ✓$C{H_3}COOH$
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Given : $K _{ sp } Cu ( OH )_2=1 \times 10^{-20}$
$\operatorname{Take} \frac{2.303 RT }{ F }=0.059 \,V$
The reduction potential at $pH =14$ for the above couple is $(-) x \times 10^{-2}\,V$. The value of $x$ is $........$.
$2Ph - CHO\xrightarrow{{KOH}}Ph - C{H_2}OH + PhCO_2^ - $