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3.2 , motion in plane — Physics STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 SciencePhysics3.2 , motion in plane1 Mark
MCQ
A projectile is fired at a speed of $100\, m/sec$ at an angle of $37^o$ above the horizontal. At the highest point, the projectile breaks into two parts of mass ratio $1:3$, the smaller coming to rest. Then the distance of heavier part from the launching point is ........... $m$.
  • A
    $480$
  • B
    $960$
  • ✓
    $1120$
  • D
    $1440$
✓

Answer

Correct option: C.
$1120$
c
$\mathrm{By} \mathrm{COLM}$

$\operatorname{mucos} \theta=\left(\frac{3 \mathrm{m}}{4}\right) \mathrm{V}^{1} \Rightarrow \mathrm{V}^{1}=\frac{4}{3}(\mathrm{u} \cos \theta)$

so total Range become

$\frac{\mathrm{R}}{2}+\frac{2 \mathrm{R}}{3}=\frac{3 \mathrm{R}+4 \mathrm{R}}{6}=\frac{7 \mathrm{R}}{6}$

$\mathrm{R}=\frac{\mathrm{u}^{2} \sin 2 \theta}{\mathrm{g}}=\frac{100 \times 100 \times 2 \times \frac{3}{5} \times \frac{4}{5}}{10}$

$=960 \mathrm{m}$

Total range $=7 / 6 \times 960=1120 \mathrm{m}$

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