MCQ
A proton accelerated by a potential difference $500 \ KV$ moves though a transverse magnetic field of $0.51T$ as shown in figure. The angle $0$ through which the proton deviates from the initial direction of its motion is


- A$15^{\circ}$
- ✓$30^{\circ}$
- C$45^{\circ}$
- D$60^{\circ}$