MCQ
A proton accelerated by a potential difference $500 \ KV$ moves though a transverse magnetic field of $0.51T$ as shown in figure. The angle $0$ through which the proton deviates from the initial direction of its motion is
  • A
    $15^{\circ}$
  • $30^{\circ}$
  • C
    $45^{\circ}$
  • D
    $60^{\circ}$

Answer

Correct option: B.
$30^{\circ}$
$30^{\circ}$

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