MCQ
$A$ proton and an $\alpha$-particle are accelerated through a potential difference of $100 V$. The ratio of the wavelength associated with the proton to that associated with an $\alpha$-particle is
- A$\sqrt 2 :1$
- B$2:1$
- ✓$2\sqrt 2 :1$
- D$\frac{1}{{2\sqrt 2 }}:1$


