Question
A proton and an electron are accelerated by same potential difference have de-Broglie wavelength $\lambda_p$ and $\lambda_e$.
✓
Answer
de Broglie wavelength of a particle of mass $m$ moving under a potential $v$ is given my:
$\lambda=\frac{h}{\sqrt{2 m e V}}$
So it is clear that de Broglie wavelength is inversely proportional to the square root of the mass of the material. Now mass of electron is less that the mass of the proton so de Broglie wavelength of electron will be greater than that of proton. So,
the answer is option $(C).$
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