A proton is moves on circular path with its constant angular speed then correct relation between its magnetic moment and angular momentum
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Two long current carrying conductors are placed parallel to each other at a distance of $8 \,cm$ between them. The magnitude of magnetic field produced at mid-point between the two conductors due to current flowing in them is $300 \,\mu T$. The equal current flowing in the two conductors is ...............
A proton is projected with velocity $\overrightarrow{ V }=2 \hat{ i }$ in a region where magnetic field $\overrightarrow{ B }=(\hat{i}+3 \hat{j}+4 \hat{k})\; \mu T$ and electric field $\overrightarrow{ E }=10 \hat{ i } \;\mu V / m .$ Then find out the net acceleration of proton (in $m / s ^{2}$)
A long insulated copper wire is closely wound as a spiral of ' $N$ ' turns. The spiral has inner radius ' $a$ ' and outer radius ' $b$ '. The spiral lies in the $X-Y$ plane and a steady current ' $I$ ' flows through the wire. The $Z$-component of the magnetic field at the center of the spiral is
Figure shows the cross-sectional view of the hollow cylindrical conductor with inner radius '$R$' and outer radius '$2R$', cylinder carrying uniformly distributed current along it's axis. The magnetic induction at point '$P$' at a distance $\frac{{3R}}{2}$ from the axis of the cylinder will be
Ionized hydrogen atoms and $\alpha$ -particles with same momenta enters perpendicular to a constant magnetic field $B$. The ratio of their radii of their paths $\mathrm{r}_{\mathrm{H}}: \mathrm{r}_{\alpha}$ will be
The expression for the torque acting on a coil having area of cross-section $A$, number of turns $n$, placed in a magnetic field of strength $B$, making an angle $\theta $ with the normal to the plane of the coil, when a current $i$ is flowing in it, will be
A long straight wire, carrying current $I,$ is bent at its midpoint to from an angle of $45^o.$ Induction of magnetic field at point $P,$ distant $R$ from point of bending is equal to :
A solenoid is $1.0$ $ metre$ long and it has $4250$ $turns$. If a current of $5.0$ $ampere$ is flowing through it, what is the magnetic field at its centre $[{\mu _0} = 4\pi \times {10^{ - 7}}\,weber/amp - m]$