MCQ
A quadratic polynomial whose zeros are $\frac{3}{5}$ and $\frac{-1}{2}$ is :
  • A
    $ 10 x^2+x+3 $
  • B
    $ 10 x^2+x-3 $
  • C
    $ 10 x^2-x+3 $
  • $ 10 x^2-x-3 $

Answer

Correct option: D.
$ 10 x^2-x-3 $
Let $\alpha$ and $\beta$ be the zeros of the required quadratic polynomial.
Then, we have
$\alpha+\beta=\frac{3}{5}+\Big(-\frac{1}{2}\Big)$
$=\frac{6-5}{10}=\frac{1}{10}$
$\alpha\beta=\frac{3}{5}\times\Big(-\frac{1}{2}\Big)=-\frac{3}{10}$
Now, a quadratic polynomial whose zeros are $\alpha$ and $\beta$ is given by
$\text{p}(\text{x})=\text{x}^2-(\alpha+\beta)\text{x}+\alpha\beta$
$\Rightarrow\text{p}(\text{x})=\text{x}^2-\Big(\frac{1}{10}\Big)\text{x}+\Big(-\frac{3}{10}\Big)$
$=\text{x}^2-\frac{1}{10}\text{x}-\frac{3}{10}$ or $10\text{x}^2-\text{x}-3$

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