Question
A random variable has the following probability distribution:
$X = X_i$ 1 2 3 4
$P(X = X_i)$ k 2k 3k 4k
Write the value of $\text{P}(\text{X}\geq3).$

Answer

Here,
$X = X_i$ 1 2 3 4
$P(X = X_i)$ k 2k 3k 4k
Since, $\sum\text{P}(\text{X})=1$
$⇒ P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 1$
$ ⇒ k + 2k + 3k + 4k =1$
$​​​​​​​ ⇒ 10k = 1$
$\Rightarrow\text{k}=\frac{1}{10}$
$\text{P}(\text{X}\geq3)$
$= P(X = 3) + P(X = 4)$
$= 3k + 4k$
$ =7k =\frac{1}{10}$ $\text{P}(\text{X}\geq3)=\frac{7}{10}$

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