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Probability Distributions — Maths STD 12 Science — Question

Maharashtra BoardEnglish MediumSTD 12 ScienceMathsProbability Distributions2 Marks
MCQ
A random variable X has the following probability distribution:
X = x-3-2-10123
P$(X = x)$0.050.100.150.200.250.150.10
Then $\mathrm{P}(\mathrm{X}$ is odd $)=$
  • A
    0.45
  • ✓
    0.55
  • C
    0.65
  • D
    0.75
✓

Answer

Correct option: B.
0.55
(B)
$\begin{aligned} & \mathrm{P}(\mathrm{X} \text { is odd }) \\ & =\mathrm{P}(\mathrm{X}=-3)+\mathrm{P}(\mathrm{X}=-1)+\mathrm{P}(\mathrm{X}=1)+\mathrm{P}(\mathrm{X}=3) \\ & =0.05+0.15+0.25+0.10=0.55\end{aligned}$

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