MCQ
A rationalising factor $3 \sqrt{3}$ is
- A$\sqrt{3}$
- ✓$3^{2 / 3}$
- C$\frac{1}{3}$
- D$3^{1 / 3}$
✓
Answer
Correct option: B.
$3^{2 / 3}$
(b)
A rationalising factor of $\sqrt[n]{a}$ is $\sqrt[n]{a^{n-1}}$. Therefore, a rationalising factor of $\sqrt[3]{3}$ is $\sqrt[3]{3^{3-1}}=\sqrt[3]{3^2}=3^{2 / 3}$.
A rationalising factor of $\sqrt[n]{a}$ is $\sqrt[n]{a^{n-1}}$. Therefore, a rationalising factor of $\sqrt[3]{3}$ is $\sqrt[3]{3^{3-1}}=\sqrt[3]{3^2}=3^{2 / 3}$.
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