MCQ
A reaction between methyl magnesium bromide and ethyl alcohol gives
- ✓Methane
- BEthane
- CPropane
- DButane

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$\,\begin{array}{*{20}{c}}
{\,C{H_3} - \,CH - \,CH = C{H_2}\,\xrightarrow{{B{r_2}/aq.NaCl}}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
$\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,O} \\
{\,\,\,\,\,\,\,\,||} \\
{C{H_3} - C - H}
\end{array}$ $\mathop {\xrightarrow{{HCN}}}\limits_{\mathop O\limits^\Theta H} (A)\mathop {\xrightarrow{{{H_2}O/{H^ \oplus }}}}\limits_\Delta $ Product
Product will be :
Product $(b)$ of above reaction is