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A reaction rate constant is given by $k = 1.2 \times 10^{14}  \,e^{-25000/RT} \,sec^{-1}$.It means

• A
  $\log\,  k$ versus $\log\,  T$ will give a straight line with a slope as $25000$
• B
  $\log\,  k$ versus $\log\, T$ will give a straight line with a slope as $-2500$
• C
  $\log\, k$ versus $\log\,  T$ will give a straight line with a slope as $-25000$
• ✓
  $\log\, k$ versus $1/T$ will give a straight line