MCQ
A reaction rate constant is given by $k = 1.2 \times {10^{14}}{e^{ - (25000/RT)}}\,{\sec ^{ - 1}}$ It means
- A$\log \,k$ versus $\log \,T$ will give a straight line with slope as $-25000$
- B$\log \,k$ versus $T$ will give a straight line with slope as $-25000$
- C$\log \,k$ versus $\log \,1/T$ will give a straight line with slope as $-25000$
- ✓$\log \,k$ versus $1/T$ will give a straight line