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STD 11 - 4.1 complex nubers — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 11 - 4.1 complex nubers4 Marks
MCQ
A rectangle is constructed in the complex plane with its sides parallel to the axes and its centre is situated at the origin. If one of the vertices of the rectangle is $a + ib\sqrt 3 $, then the area of the rectangle is
  • A
    $ab\sqrt 3 $
  • B
    $2ab\sqrt 3 $
  • C
    $3ab\sqrt 3 $
  • ✓
    $4ab\sqrt 3 $
✓

Answer

Correct option: D.
$4ab\sqrt 3 $
d
(d) Area of required rectangle $= 4×$area of $OABC$
$ = 4 \times a \times b\sqrt 3 = 4ab\sqrt 3 $.

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