Hence the flux through the coil is $\phi=\vec{B} . \vec{A}=B A \cos \theta$
Hence the induced emf $=$ Rate of change of flux $=-\frac{d \phi}{d t}=B A \sin \theta \frac{d \theta}{d t}=B A \omega \sin \theta$
Hence it is minimum when $\theta=0^{\circ}, 180^{\circ}$
Which means when the plane of coil is at right angle to the magnetic field.
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$(A)$ the process during the path $\mathrm{A} \rightarrow \mathrm{B}$ is isothermal
$(B)$ heat flows out of the gas during the path $\mathrm{B} \rightarrow \mathrm{C} \rightarrow \mathrm{D}$
$(C)$ work done during the path $\mathrm{A} \rightarrow \mathrm{B} \rightarrow \mathrm{C}$ is zero
$(D)$ positive work is done by the gas in the cycle $ABCDA$
