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Perimeter and Area — MATHS STD 7 — Question

Gujarat BoardEnglish MediumSTD 7MATHSPerimeter and Area2 Marks
Question
A rectangular field is $48m$ long and $12m$ wide. How many right triangular flower beds can be laid in this field, if sides including the right angle measure $2m$ and $4m,$ respectively$?$
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Answer

Given, dimenstions of a rectangular field $= 48m \times 12m$ and
dimensions of a right angled triangle $= 2m \times 4m$
$\therefore$ Number of right triangle florer beds $=\frac{\text{Area of filed}}{\text{Area of right angled triangle}}$
$=\frac{48\times12}{\frac{1}{2}\times2\times4}= 144$
$\Big[\because$ area of rectangle $=$ lenght $\times $ breadth and area of a right angled $=\frac{1}{2}\times\text{height}\times\text{breadth}\Big]$

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