Question
A rectangular field is $48m$ long and $20m$ wide. How many right triangular flower beds, whose sides containing the right angle measure $12m$ and $5m$ can be laid in this field?
✓
Answer
We have,
Length of the rectangular field $=48 \mathrm{~m}$
Breadth of the rectangular field $=20 \mathrm{~m}$
Area of the rectangular field $=$ Length $\times$ Breadth $=48 \mathrm{~m} \times 20 \mathrm{~m}=960 \mathrm{~m}^2$
Area of one right triangular flower bed $=\frac{1}{2}(12 \mathrm{~m} \times 5 \mathrm{~m})=30 \mathrm{~m}^2$
Therefore,
Required number of right triangular flower beds $=\frac{960_{\mathrm{m}^2}}{30_{\mathrm{m}}}=32$
Length of the rectangular field $=48 \mathrm{~m}$
Breadth of the rectangular field $=20 \mathrm{~m}$
Area of the rectangular field $=$ Length $\times$ Breadth $=48 \mathrm{~m} \times 20 \mathrm{~m}=960 \mathrm{~m}^2$
Area of one right triangular flower bed $=\frac{1}{2}(12 \mathrm{~m} \times 5 \mathrm{~m})=30 \mathrm{~m}^2$
Therefore,
Required number of right triangular flower beds $=\frac{960_{\mathrm{m}^2}}{30_{\mathrm{m}}}=32$
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