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Areas of Triangles and Quadrilaterals — Maths STD 9 — Question

Gujarat BoardEnglish MediumSTD 9MathsAreas of Triangles and Quadrilaterals5 Marks
Question
A rectangular lawn, 75m by 60m, has two roads, each road 4m wide, running through the middle of the lawn, one parallel to length and the other parallel to breadth, as shown in the figure. Find the cost of gravelling the rosds at ₹ 50 per m2.

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Answer

For road ABCD, i.e. for rectangle ABCD,
Length = 75m
Breadth = 4m
Area of road ABCD = Length × Breadth = 75m × 4m = 300 m2
For road PQRS, i.e. for rectangle PQRS,
Length = 60m
Breadth = 4m
Area of road PQRS = Length × Breadth = 60m × 4m = 240m2
For road EFGH, i.e. for square EFGH,
Side = 4m
Area of road EFGH = (Side)2 = (4)2 = 16m2
Total area of road for gravelling
= Area of road ABCD + Area of road PQRS - Area of road EFGH
= 300 + 240 - 16
= 524m2
Cost of gravelling the road = ₹ 50 per m2
$\therefore$ Cost of gravelling 524m2 road = ₹ (50 × 524) = ₹ 26,200

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