MCQ
A rectangular loop carrying a current i1​, is situated near a long straight wire carrying a steady current i2​. The wire is parallel to one of the sides of the loop and is in the plane of the loop as shown in the figure. Then the current loop will:

  • A
    Move away from the wire
  • B
    Move towards the wire
  • C
    Remain stationary
  • D
    Rotate about an axis parallel to the wire

Answer

  1. Move towards the wire

Explanation:

The magnetic field due to the straight current current carrying wire decreases with increasing distance from the wire.

Thus the magnetic field is stronger at the side closer to wire and weaker at the other.

Force on each segment of wire is BIL

Hence force acting on nearer side towards the wire is greater than the force acting on farther side away from wire. Hence the net force on loop is towards the wire.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

In an insulator, the forbidden energy gap between valence band and conduction band is of the following order :

The ratio of speed of an electron in ground state in Bohrs first orbit of hydrogen atom to velocity of light in air is

(a)  

(b)

(c)   

(d)

For a medium, refractive indices for violet, red and yellow are 1.62, 1.52 and 1.55 respectively, then dispersive power of medium will be

(a) 0.65

(b) 0.22

(c) 0.18

(d) 0.02

The centre of a wheel rolling on a plane surface moves with a speed v0. A particle on the rim of the wheel at the same level as the centre will be moving at speed:

  1. $\text{Zero.}$

  2. $\text{v}_0$

  3. $\sqrt2\text{v}_0$

  4. $2\text{v}_0$

Two capacitors of capacities   and  are charged to voltages   and   respectively. There will be no exchange of energy in connecting them in parallel, if

(a)  

(b)  

(c)  

(d)  

The shortest wavelength in Balmer’s series for Hydrogen atom is ...A... and this is obtained by substituting ...B ... in Balmer’s formula. Here, A and B refer to?

Angle between equipotential surface and lines of force is

(a) Zero

(b) 180°

(c) 90°

(d) 45°

The two slits at a distance of 1 mm are illuminated by the light of wavelength 6.5 . The interference fringes  are observed on a screen placed at a distance of 1m. The distance between third dark fringe and fifth bright fringe will be

(a) 0.65 mm

(b) 1.63 mm

(c) 3.25 mm

(d) 4.88 mm

For harder X-rays:
  1. The wavelength is higher.
  2. The intensity is higher.
  3. The frequency is higher.
  4. The photon energy is higher.

A radioactive substance emits

(a) a-rays

(b) b-rays

(c) g-rays

(d) All of these