Question
A rectangular plot is given for constructing a house, having a measurement of $40\ m$ long and $15\ m$ in the front. According to the laws, a minimum of $3\ m$, wide space should be left in the front and back each and $2\ m$ wide space on each of other sides. Find the largest area where house can be constructed. 

Answer

The length of the rectangular plot $=40 \mathrm{~m}$ And the breath of the plot $=15 \mathrm{~m}$ As a minimum of $3 \ m$ wide space should be left in the front and back $2 \ m$ wide space each of other side, so the largest area where the house can be constructed. Length $\times$ Breadth $=[40-2(3)][15-2(2)]=34 \times 11=374 \mathrm{~m}^2$

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