Question
A resistance is connected to an AC source. If a capacitor is included in the series circuit, will the average power absorbed by the resistance increase or decrease? If an inductor of small inductance is also included in the series circuit, will the average power absorbed increase or decrease further?

Answer

If capacitor is included$\text{Z}=\sqrt{\text{R}^2+\text{X}_\text{C}^2}$
Hence, impedence increases so $I_{rms}$ decreases. Hence, $I_{rms}{}^2$ R decreases. If the inductor of small inductance is also included then,$\text{Z}=\sqrt{\text{R}^2+\big(\text{X}_\text{C}-\text{X}_\text{L}\big)^2}$
Now, impedance gets decreased hence $I_{rms}$ increases and $I_{rms}{}^2$ R increases.

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