Download App

STD 12 - 4. Moving charges and magnetism — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 12 - 4. Moving charges and magnetism4 Marks
MCQ
A rigid square loop of side $a$ and carrying current $I_2$ is laying on a horizontal surface near a long current $I_1$ wire in the same plane as shown in figure. The net force on the loop due to the wire will be
  • A
    Repulsive and equal to $\frac{{{\mu _0}{I_1}{I_2}}}{{2\pi }}$
  • ✓
    Repulsive and equal to $\frac{{{\mu _0}{I_1}{I_2}}}{{4\pi }}$
  • C
    Zero
  • D
    Attractive and equal to $\frac{{{\mu _0}{I_1}{I_2}}}{{3\pi }}$
✓

Answer

Correct option: B.
Repulsive and equal to $\frac{{{\mu _0}{I_1}{I_2}}}{{4\pi }}$
b
${{\text{F}}_3}{\text{& }}{{\text{F}}_4}\,{\text{cancel}}\,{\text{each}}\,{\text{other}}{\text{. }}$

${\text{Force on PQ will be }}{{\text{F}}_1} = {2_B}{\text{Ia}}$

${\text{ = }}{{\text{I}}_2}\frac{{{\mu _0}{I_1}}}{{2\pi {\text{a}}}}{\text{a}}$

$ = \frac{{{\mu _0}I}}{{2\pi {\text{a}}}}{\text{a}}$

$ = \frac{{{\mu _0}{I_1}{I_2}}}{{2\pi }}$

Force on $RS$ will be $F_{2}=I_{2} B_{2} a$

${=\mathrm{I}_{2} \frac{\mu_{0} \mathrm{I}_{1}}{2 \pi 2 \mathrm{a}} \mathrm{a}}$

${=\frac{\mu_{0} I_{1} I_{2}}{4 \pi}}$

Net force $=\mathrm{F}_{1}-\mathrm{F}_{2}=\frac{\mu_{0} I_1 \mathrm{I}_{2}}{4 \pi}$ repulsion

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

JEE STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

In a standing wave, all particles of the medium cross the mean position with
→
A galvanometer with a resistance of $12 \,\Omega$ gives full scale deflection when a current of $3\, mA$ is passed. It is required to convert it into a voltmeter which can read up to $18\, V$. the resistance to be connected is ............... $\Omega $
→
Molybdenum is used as a target element for production of $X-$ rays because it is
→
If the value of g at the surface of the earth is $9.8$ $m/{\sec ^2}$, then the value of g at a place $480\, km$ above the surface of the earth will be .......... $m/{\sec ^2}$. (Radius of the earth is $6400\, km$)   
→
Two particles $A$ and $B$ of masses ${m_A}$ and ${m_B}$ respectively and having the same charge are moving in a plane. A uniform magnetic field exists perpendicular to this plane. The speeds of the particles are ${v_A}$ and ${v_B}$ respectively, and the trajectories are as shown in the figure. Then
→
A particle moving along the $X-$axis executes simple harmonic motion, then the force acting on it is given by

Where $A$ and $K$ are positive constants

→
An engine of a train, moving with uniform acceleration, passes the signal-post with velocity $u$ and the last compartment with velocity $v$. The velocity with which middle point of the train passes the signal post is
→
Displacement between maximum potential energy position and maximum kinetic energy position for a particle executing $S.H.M.$ is
→
The plates of a capacitor are charged to a potential difference of $320 \, volts$ and are then connected across a resistor. The potential difference across the capacitor decays exponentially with time. After $1 $ second the potential difference between the plates of the capacitor is $240 \, volts$, then after $2$ and $3$ seconds the potential difference between the plates will be
→
The resistance of a wire is $R$. If the length of the wire is doubled by stretching, then the new resistance will be
→