Question
A rocket is fired upward from the earth's surface such that it creates an acceleration of $20\, m/s^2$. If after $5\, s$ its engine is switched off, the maximum height of the rocket from the earth's surface would be......$m$
$=\frac{1}{2} a t^{2}+\frac{u^{2}}{2 g}$
$=\frac{1}{2} \times 20 \times 5^{2}+\frac{100^{2}}{20}$
$=250+500$
$=750$
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